(2x+1)(2x^2+1)=0

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Solution for (2x+1)(2x^2+1)=0 equation: 


Simplifying
(2x + 1)(2x2 + 1) = 0

Reorder the terms:
(1 + 2x)(2x2 + 1) = 0

Reorder the terms:
(1 + 2x)(1 + 2x2) = 0

Multiply (1 + 2x) * (1 + 2x2)
(1(1 + 2x2) + 2x * (1 + 2x2)) = 0
((1 * 1 + 2x2 * 1) + 2x * (1 + 2x2)) = 0
((1 + 2x2) + 2x * (1 + 2x2)) = 0
(1 + 2x2 + (1 * 2x + 2x2 * 2x)) = 0
(1 + 2x2 + (2x + 4x3)) = 0

Reorder the terms:
(1 + 2x + 2x2 + 4x3) = 0
(1 + 2x + 2x2 + 4x3) = 0

Solving
1 + 2x + 2x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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